5(2b-3)=b-30

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Solution for 5(2b-3)=b-30 equation:



5(2b-3)=b-30
We move all terms to the left:
5(2b-3)-(b-30)=0
We multiply parentheses
10b-(b-30)-15=0
We get rid of parentheses
10b-b+30-15=0
We add all the numbers together, and all the variables
9b+15=0
We move all terms containing b to the left, all other terms to the right
9b=-15
b=-15/9
b=-1+2/3

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