5(2b-1)=(3b-2)

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Solution for 5(2b-1)=(3b-2) equation: 



5(2b-1)=(3b-2)

We move all terms to the left:

5(2b-1)-((3b-2))=0

We multiply parentheses

10b-((3b-2))-5=0



We calculate terms in parentheses: -((3b-2)), so:

(3b-2)

We get rid of parentheses

3b-2

Back to the equation:

-(3b-2)



We get rid of parentheses

10b-3b+2-5=0

We add all the numbers together, and all the variables

7b-3=0

We move all terms containing b to the left, all other terms to the right

7b=3

b=3/7

b=3/7

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