5(2b+1)=3(4b-5)

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Solution for 5(2b+1)=3(4b-5) equation: 



5(2b+1)=3(4b-5)

We move all terms to the left:

5(2b+1)-(3(4b-5))=0

We multiply parentheses

10b-(3(4b-5))+5=0



We calculate terms in parentheses: -(3(4b-5)), so:

3(4b-5)

We multiply parentheses

12b-15

Back to the equation:

-(12b-15)



We get rid of parentheses

10b-12b+15+5=0

We add all the numbers together, and all the variables

-2b+20=0

We move all terms containing b to the left, all other terms to the right

-2b=-20

b=-20/-2

b=+10

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