5(2b+1)+7(4b+2)=0

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Solution for 5(2b+1)+7(4b+2)=0 equation:


Simplifying
5(2b + 1) + 7(4b + 2) = 0

Reorder the terms:
5(1 + 2b) + 7(4b + 2) = 0
(1 * 5 + 2b * 5) + 7(4b + 2) = 0
(5 + 10b) + 7(4b + 2) = 0

Reorder the terms:
5 + 10b + 7(2 + 4b) = 0
5 + 10b + (2 * 7 + 4b * 7) = 0
5 + 10b + (14 + 28b) = 0

Reorder the terms:
5 + 14 + 10b + 28b = 0

Combine like terms: 5 + 14 = 19
19 + 10b + 28b = 0

Combine like terms: 10b + 28b = 38b
19 + 38b = 0

Solving
19 + 38b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-19' to each side of the equation.
19 + -19 + 38b = 0 + -19

Combine like terms: 19 + -19 = 0
0 + 38b = 0 + -19
38b = 0 + -19

Combine like terms: 0 + -19 = -19
38b = -19

Divide each side by '38'.
b = -0.5

Simplifying
b = -0.5

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