5(2ax+3y)-4ax=2(ax-5)

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Solution for 5(2ax+3y)-4ax=2(ax-5) equation:


Simplifying
5(2ax + 3y) + -4ax = 2(ax + -5)
(2ax * 5 + 3y * 5) + -4ax = 2(ax + -5)
(10ax + 15y) + -4ax = 2(ax + -5)

Reorder the terms:
10ax + -4ax + 15y = 2(ax + -5)

Combine like terms: 10ax + -4ax = 6ax
6ax + 15y = 2(ax + -5)

Reorder the terms:
6ax + 15y = 2(-5 + ax)
6ax + 15y = (-5 * 2 + ax * 2)
6ax + 15y = (-10 + 2ax)

Solving
6ax + 15y = -10 + 2ax

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2ax' to each side of the equation.
6ax + -2ax + 15y = -10 + 2ax + -2ax

Combine like terms: 6ax + -2ax = 4ax
4ax + 15y = -10 + 2ax + -2ax

Combine like terms: 2ax + -2ax = 0
4ax + 15y = -10 + 0
4ax + 15y = -10

Add '-15y' to each side of the equation.
4ax + 15y + -15y = -10 + -15y

Combine like terms: 15y + -15y = 0
4ax + 0 = -10 + -15y
4ax = -10 + -15y

Divide each side by '4x'.
a = -2.5x-1 + -3.75x-1y

Simplifying
a = -2.5x-1 + -3.75x-1y

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