5(2a+3b+4c)=

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Solution for 5(2a+3b+4c)= equation:


Simplifying
5(2a + 3b + 4c) = 0
(2a * 5 + 3b * 5 + 4c * 5) = 0
(10a + 15b + 20c) = 0

Solving
10a + 15b + 20c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-15b' to each side of the equation.
10a + 15b + -15b + 20c = 0 + -15b

Combine like terms: 15b + -15b = 0
10a + 0 + 20c = 0 + -15b
10a + 20c = 0 + -15b
Remove the zero:
10a + 20c = -15b

Add '-20c' to each side of the equation.
10a + 20c + -20c = -15b + -20c

Combine like terms: 20c + -20c = 0
10a + 0 = -15b + -20c
10a = -15b + -20c

Divide each side by '10'.
a = -1.5b + -2c

Simplifying
a = -1.5b + -2c

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