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5(20-x)=1/2(4x+4
We move all terms to the left:
5(20-x)-(1/2(4x+4)=0
Domain of the equation: 2(4x+4)!=0We add all the numbers together, and all the variables
x∈R
5(-1x+20)-(1/2(4x+4)=0
We multiply parentheses
-5x-(1/2(4x+4)+100=0
We multiply all the terms by the denominator
-5x*2(4x+4)+100-(1=0
We add all the numbers together, and all the variables
-5x*2(4x+4)=0
Wy multiply elements
-10x^2(4=0
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