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5(20+x)=1/4(4x+4)
We move all terms to the left:
5(20+x)-(1/4(4x+4))=0
Domain of the equation: 4(4x+4))!=0We add all the numbers together, and all the variables
x∈R
5(x+20)-(1/4(4x+4))=0
We multiply parentheses
5x-(1/4(4x+4))+100=0
We multiply all the terms by the denominator
5x*4(4x+4))-(1+100*4(4x+4))=0
Wy multiply elements
20x^2(4+400x(4=0
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