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5(20+p)=2-(30+p)
We move all terms to the left:
5(20+p)-(2-(30+p))=0
We add all the numbers together, and all the variables
5(p+20)-(2-(p+30))=0
We multiply parentheses
5p-(2-(p+30))+100=0
We calculate terms in parentheses: -(2-(p+30)), so:We get rid of parentheses
2-(p+30)
determiningTheFunctionDomain -(p+30)+2
We get rid of parentheses
-p-30+2
We add all the numbers together, and all the variables
-1p-28
Back to the equation:
-(-1p-28)
5p+1p+28+100=0
We add all the numbers together, and all the variables
6p+128=0
We move all terms containing p to the left, all other terms to the right
6p=-128
p=-128/6
p=-21+1/3
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