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5(2/5x+3=-4
We move all terms to the left:
5(2/5x+3-(-4)=0
Domain of the equation: 5x+3-(-4)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
5x-(-4)!=-3
x∈R
5(2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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