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5(2/5x+2=x-4)
We move all terms to the left:
5(2/5x+2-(x-4))=0
Domain of the equation: 5x+2-(x-4))!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
5x-(x-4))!=-2
x∈R
5(2=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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