5(2-c)=-10(2c-4)-6(3c+1)

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Solution for 5(2-c)=-10(2c-4)-6(3c+1) equation: 



5(2-c)=-10(2c-4)-6(3c+1)

We move all terms to the left:

5(2-c)-(-10(2c-4)-6(3c+1))=0

We add all the numbers together, and all the variables

5(-1c+2)-(-10(2c-4)-6(3c+1))=0

We multiply parentheses

-5c-(-10(2c-4)-6(3c+1))+10=0



We calculate terms in parentheses: -(-10(2c-4)-6(3c+1)), so:

-10(2c-4)-6(3c+1)

We multiply parentheses

-20c-18c+40-6

We add all the numbers together, and all the variables

-38c+34

Back to the equation:

-(-38c+34)



We get rid of parentheses

-5c+38c-34+10=0

We add all the numbers together, and all the variables

33c-24=0

We move all terms containing c to the left, all other terms to the right

33c=24

c=24/33

c=8/11

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