5(2-3x)=2-(x+1)

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Solution for 5(2-3x)=2-(x+1) equation: 



5(2-3x)=2-(x+1)

We move all terms to the left:

5(2-3x)-(2-(x+1))=0

We add all the numbers together, and all the variables

5(-3x+2)-(2-(x+1))=0

We multiply parentheses

-15x-(2-(x+1))+10=0



We calculate terms in parentheses: -(2-(x+1)), so:

2-(x+1)

determiningTheFunctionDomain
-(x+1)+2

We get rid of parentheses

-x-1+2

We add all the numbers together, and all the variables

-1x+1

Back to the equation:

-(-1x+1)



We get rid of parentheses

-15x+1x-1+10=0

We add all the numbers together, and all the variables

-14x+9=0

We move all terms containing x to the left, all other terms to the right

-14x=-9

x=-9/-14

x=9/14

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