5(2-2x)+3(x-6)=16-4(6+2x)+x

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Solution for 5(2-2x)+3(x-6)=16-4(6+2x)+x equation: 



5(2-2x)+3(x-6)=16-4(6+2x)+x

We move all terms to the left:

5(2-2x)+3(x-6)-(16-4(6+2x)+x)=0

We add all the numbers together, and all the variables

5(-2x+2)+3(x-6)-(16-4(2x+6)+x)=0

We multiply parentheses

-10x+3x-(16-4(2x+6)+x)+10-18=0



We calculate terms in parentheses: -(16-4(2x+6)+x), so:

16-4(2x+6)+x

determiningTheFunctionDomain
-4(2x+6)+x+16

We add all the numbers together, and all the variables

x-4(2x+6)+16

We multiply parentheses

x-8x-24+16

We add all the numbers together, and all the variables

-7x-8

Back to the equation:

-(-7x-8)



We add all the numbers together, and all the variables

-7x-(-7x-8)-8=0

We get rid of parentheses

-7x+7x+8-8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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