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5(2+x)=-2(x-3)+5x
We move all terms to the left:
5(2+x)-(-2(x-3)+5x)=0
We add all the numbers together, and all the variables
5(x+2)-(-2(x-3)+5x)=0
We multiply parentheses
5x-(-2(x-3)+5x)+10=0
We calculate terms in parentheses: -(-2(x-3)+5x), so:We get rid of parentheses
-2(x-3)+5x
We add all the numbers together, and all the variables
5x-2(x-3)
We multiply parentheses
5x-2x+6
We add all the numbers together, and all the variables
3x+6
Back to the equation:
-(3x+6)
5x-3x-6+10=0
We add all the numbers together, and all the variables
2x+4=0
We move all terms containing x to the left, all other terms to the right
2x=-4
x=-4/2
x=-2
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