5(2+v)-v=2(v+1)

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Solution for 5(2+v)-v=2(v+1) equation: 



5(2+v)-v=2(v+1)

We move all terms to the left:

5(2+v)-v-(2(v+1))=0

We add all the numbers together, and all the variables

5(v+2)-v-(2(v+1))=0

We add all the numbers together, and all the variables

-1v+5(v+2)-(2(v+1))=0

We multiply parentheses

-1v+5v-(2(v+1))+10=0



We calculate terms in parentheses: -(2(v+1)), so:

2(v+1)

We multiply parentheses

2v+2

Back to the equation:

-(2v+2)



We add all the numbers together, and all the variables

4v-(2v+2)+10=0

We get rid of parentheses

4v-2v-2+10=0

We add all the numbers together, and all the variables

2v+8=0

We move all terms containing v to the left, all other terms to the right

2v=-8

v=-8/2

v=-4

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