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5(2+n)=3/5(5+10n)
We move all terms to the left:
5(2+n)-(3/5(5+10n))=0
Domain of the equation: 5(5+10n))!=0We add all the numbers together, and all the variables
n∈R
5(n+2)-(3/5(10n+5))=0
We multiply parentheses
5n-(3/5(10n+5))+10=0
We multiply all the terms by the denominator
5n*5(10n+5))-(3+10*5(10n+5))=0
Wy multiply elements
25n^2(1+50n(1=0
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