5(2+2c)=6(3c-2c)

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Solution for 5(2+2c)=6(3c-2c) equation:


Simplifying
5(2 + 2c) = 6(3c + -2c)
(2 * 5 + 2c * 5) = 6(3c + -2c)
(10 + 10c) = 6(3c + -2c)

Combine like terms: 3c + -2c = 1c
10 + 10c = 6(1c)

Remove parenthesis around (1c)
10 + 10c = 6 * 1c

Multiply 6 * 1
10 + 10c = 6c

Solving
10 + 10c = 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
10 + 10c + -6c = 6c + -6c

Combine like terms: 10c + -6c = 4c
10 + 4c = 6c + -6c

Combine like terms: 6c + -6c = 0
10 + 4c = 0

Add '-10' to each side of the equation.
10 + -10 + 4c = 0 + -10

Combine like terms: 10 + -10 = 0
0 + 4c = 0 + -10
4c = 0 + -10

Combine like terms: 0 + -10 = -10
4c = -10

Divide each side by '4'.
c = -2.5

Simplifying
c = -2.5

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