5(1z+1)=50

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Solution for 5(1z+1)=50 equation:



5(1z+1)=50
We move all terms to the left:
5(1z+1)-(50)=0
We add all the numbers together, and all the variables
5(z+1)-50=0
We multiply parentheses
5z+5-50=0
We add all the numbers together, and all the variables
5z-45=0
We move all terms containing z to the left, all other terms to the right
5z=45
z=45/5
z=9

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