5(1y-4)=7(2y+1)

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Solution for 5(1y-4)=7(2y+1) equation:


Simplifying
5(1y + -4) = 7(2y + 1)

Reorder the terms:
5(-4 + 1y) = 7(2y + 1)
(-4 * 5 + 1y * 5) = 7(2y + 1)
(-20 + 5y) = 7(2y + 1)

Reorder the terms:
-20 + 5y = 7(1 + 2y)
-20 + 5y = (1 * 7 + 2y * 7)
-20 + 5y = (7 + 14y)

Solving
-20 + 5y = 7 + 14y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-14y' to each side of the equation.
-20 + 5y + -14y = 7 + 14y + -14y

Combine like terms: 5y + -14y = -9y
-20 + -9y = 7 + 14y + -14y

Combine like terms: 14y + -14y = 0
-20 + -9y = 7 + 0
-20 + -9y = 7

Add '20' to each side of the equation.
-20 + 20 + -9y = 7 + 20

Combine like terms: -20 + 20 = 0
0 + -9y = 7 + 20
-9y = 7 + 20

Combine like terms: 7 + 20 = 27
-9y = 27

Divide each side by '-9'.
y = -3

Simplifying
y = -3

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