5(1y+2)+1y=3(1y-1)+1

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Solution for 5(1y+2)+1y=3(1y-1)+1 equation: 



5(1y+2)+1y=3(1y-1)+1

We move all terms to the left:

5(1y+2)+1y-(3(1y-1)+1)=0

We add all the numbers together, and all the variables

5(y+2)+1y-(3(y-1)+1)=0

We add all the numbers together, and all the variables

y+5(y+2)-(3(y-1)+1)=0

We multiply parentheses

y+5y-(3(y-1)+1)+10=0



We calculate terms in parentheses: -(3(y-1)+1), so:

3(y-1)+1

We multiply parentheses

3y-3+1

We add all the numbers together, and all the variables

3y-2

Back to the equation:

-(3y-2)



We add all the numbers together, and all the variables

6y-(3y-2)+10=0

We get rid of parentheses

6y-3y+2+10=0

We add all the numbers together, and all the variables

3y+12=0

We move all terms containing y to the left, all other terms to the right

3y=-12

y=-12/3

y=-4

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