5(1c+2)=2(2c+11)

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Solution for 5(1c+2)=2(2c+11) equation:


Simplifying
5(1c + 2) = 2(2c + 11)

Reorder the terms:
5(2 + 1c) = 2(2c + 11)
(2 * 5 + 1c * 5) = 2(2c + 11)
(10 + 5c) = 2(2c + 11)

Reorder the terms:
10 + 5c = 2(11 + 2c)
10 + 5c = (11 * 2 + 2c * 2)
10 + 5c = (22 + 4c)

Solving
10 + 5c = 22 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
10 + 5c + -4c = 22 + 4c + -4c

Combine like terms: 5c + -4c = 1c
10 + 1c = 22 + 4c + -4c

Combine like terms: 4c + -4c = 0
10 + 1c = 22 + 0
10 + 1c = 22

Add '-10' to each side of the equation.
10 + -10 + 1c = 22 + -10

Combine like terms: 10 + -10 = 0
0 + 1c = 22 + -10
1c = 22 + -10

Combine like terms: 22 + -10 = 12
1c = 12

Divide each side by '1'.
c = 12

Simplifying
c = 12

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