5(11c-18)=3(2c+7)

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Solution for 5(11c-18)=3(2c+7) equation: 



5(11c-18)=3(2c+7)

We move all terms to the left:

5(11c-18)-(3(2c+7))=0

We multiply parentheses

55c-(3(2c+7))-90=0



We calculate terms in parentheses: -(3(2c+7)), so:

3(2c+7)

We multiply parentheses

6c+21

Back to the equation:

-(6c+21)



We get rid of parentheses

55c-6c-21-90=0

We add all the numbers together, and all the variables

49c-111=0

We move all terms containing c to the left, all other terms to the right

49c=111

c=111/49

c=2+13/49

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