5(10x+2)-(3x-4)=41

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Solution for 5(10x+2)-(3x-4)=41 equation: 



5(10x+2)-(3x-4)=41

We move all terms to the left:

5(10x+2)-(3x-4)-(41)=0

We multiply parentheses

50x-(3x-4)+10-41=0

We get rid of parentheses

50x-3x+4+10-41=0

We add all the numbers together, and all the variables

47x-27=0

We move all terms containing x to the left, all other terms to the right

47x=27

x=27/47

x=27/47

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