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5(10k+1)+2(2+8k)=50k+5+2(2+8k)
We move all terms to the left:
5(10k+1)+2(2+8k)-(50k+5+2(2+8k))=0
We add all the numbers together, and all the variables
5(10k+1)+2(8k+2)-(50k+5+2(8k+2))=0
We multiply parentheses
50k+16k-(50k+5+2(8k+2))+5+4=0
We calculate terms in parentheses: -(50k+5+2(8k+2)), so:We add all the numbers together, and all the variables
50k+5+2(8k+2)
determiningTheFunctionDomain 50k+2(8k+2)+5
We multiply parentheses
50k+16k+4+5
We add all the numbers together, and all the variables
66k+9
Back to the equation:
-(66k+9)
66k-(66k+9)+9=0
We get rid of parentheses
66k-66k-9+9=0
We add all the numbers together, and all the variables
=0
k=0/1
k=0
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