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5(10+3b)=105-8b+4(11-4b)
We move all terms to the left:
5(10+3b)-(105-8b+4(11-4b))=0
We add all the numbers together, and all the variables
5(3b+10)-(105-8b+4(-4b+11))=0
We multiply parentheses
15b-(105-8b+4(-4b+11))+50=0
We calculate terms in parentheses: -(105-8b+4(-4b+11)), so:We get rid of parentheses
105-8b+4(-4b+11)
determiningTheFunctionDomain -8b+4(-4b+11)+105
We multiply parentheses
-8b-16b+44+105
We add all the numbers together, and all the variables
-24b+149
Back to the equation:
-(-24b+149)
15b+24b-149+50=0
We add all the numbers together, and all the variables
39b-99=0
We move all terms containing b to the left, all other terms to the right
39b=99
b=99/39
b=2+7/13
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