5(1-2x)+41=3(2-x)

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Solution for 5(1-2x)+41=3(2-x) equation: 



5(1-2x)+41=3(2-x)

We move all terms to the left:

5(1-2x)+41-(3(2-x))=0

We add all the numbers together, and all the variables

5(-2x+1)-(3(-1x+2))+41=0

We multiply parentheses

-10x-(3(-1x+2))+5+41=0



We calculate terms in parentheses: -(3(-1x+2)), so:

3(-1x+2)

We multiply parentheses

-3x+6

Back to the equation:

-(-3x+6)



We add all the numbers together, and all the variables

-10x-(-3x+6)+46=0

We get rid of parentheses

-10x+3x-6+46=0

We add all the numbers together, and all the variables

-7x+40=0

We move all terms containing x to the left, all other terms to the right

-7x=-40

x=-40/-7

x=5+5/7

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