5(1+z)=3(z+4)

Solution for 5(1+z)=3(z+4) equation:

5(1+z)=3(z+4)

We move all terms to the left:

5(1+z)-(3(z+4))=0

We add all the numbers together, and all the variables

5(z+1)-(3(z+4))=0

We multiply parentheses

5z-(3(z+4))+5=0


We calculate terms in parentheses: -(3(z+4)), so:

3(z+4)

We multiply parentheses

3z+12

Back to the equation:

-(3z+12)


We get rid of parentheses

5z-3z-12+5=0

We add all the numbers together, and all the variables

2z-7=0

We move all terms containing z to the left, all other terms to the right

2z=7

z=7/2

z=3+1/2