5(1+c)=8(c+2)

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Solution for 5(1+c)=8(c+2) equation:



5(1+c)=8(c+2)
We move all terms to the left:
5(1+c)-(8(c+2))=0
We add all the numbers together, and all the variables
5(c+1)-(8(c+2))=0
We multiply parentheses
5c-(8(c+2))+5=0
We calculate terms in parentheses: -(8(c+2)), so:
8(c+2)
We multiply parentheses
8c+16
Back to the equation:
-(8c+16)
We get rid of parentheses
5c-8c-16+5=0
We add all the numbers together, and all the variables
-3c-11=0
We move all terms containing c to the left, all other terms to the right
-3c=11
c=11/-3
c=-3+2/3

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