5(1+4h)+2h=27=

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Solution for 5(1+4h)+2h=27= equation: 



5(1+4h)+2h=27=

We move all terms to the left:

5(1+4h)+2h-(27)=0

We add all the numbers together, and all the variables

5(4h+1)+2h-27=0

We add all the numbers together, and all the variables

2h+5(4h+1)-27=0

We multiply parentheses

2h+20h+5-27=0

We add all the numbers together, and all the variables

22h-22=0

We move all terms containing h to the left, all other terms to the right

22h=22

h=22/22

h=1

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