5(1+2y)=1/2(8+20y)

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Solution for 5(1+2y)=1/2(8+20y) equation: 



5(1+2y)=1/2(8+20y)

We move all terms to the left:

5(1+2y)-(1/2(8+20y))=0



Domain of the equation: 2(8+20y))!=0

y∈R



We add all the numbers together, and all the variables

5(2y+1)-(1/2(20y+8))=0

We multiply parentheses

10y-(1/2(20y+8))+5=0

We multiply all the terms by the denominator


10y*2(20y+8))-(1+5*2(20y+8))=0

Wy multiply elements

20y^2(2+10y(2=0

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