5(-8z+1)+8=20(2z-3)+57

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Solution for 5(-8z+1)+8=20(2z-3)+57 equation: 



5(-8z+1)+8=20(2z-3)+57

We move all terms to the left:

5(-8z+1)+8-(20(2z-3)+57)=0

We multiply parentheses

-40z-(20(2z-3)+57)+5+8=0



We calculate terms in parentheses: -(20(2z-3)+57), so:

20(2z-3)+57

We multiply parentheses

40z-60+57

We add all the numbers together, and all the variables

40z-3

Back to the equation:

-(40z-3)



We add all the numbers together, and all the variables

-40z-(40z-3)+13=0

We get rid of parentheses

-40z-40z+3+13=0

We add all the numbers together, and all the variables

-80z+16=0

We move all terms containing z to the left, all other terms to the right

-80z=-16

z=-16/-80

z=1/5

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