5(-6y)(+9y)=-15+5

Solution for 5(-6y)(+9y)=-15+5 equation:

5(-6y)(+9y)=-15+5

We move all terms to the left:

5(-6y)(+9y)-(-15+5)=0

We add all the numbers together, and all the variables

5(-6y)(+9y)-(-10)=0

We add all the numbers together, and all the variables

5(-6y)(+9y)+10=0

We multiply parentheses ..

5(-54y^2)+10=0

We multiply parentheses

-270y^2+10=0

a = -270; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·(-270)·10
Δ = 10800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10800}=\sqrt{3600*3}=\sqrt{3600}*\sqrt{3}=60\sqrt{3}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{3}}{2*-270}=\frac{0-60\sqrt{3}}{-540}
=-\frac{60\sqrt{3}}{-540}
=-\frac{\sqrt{3}}{-9}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{3}}{2*-270}=\frac{0+60\sqrt{3}}{-540}
=\frac{60\sqrt{3}}{-540}
=\frac{\sqrt{3}}{-9}
$