5(-3+4c)=4(2c+4)+12c

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Solution for 5(-3+4c)=4(2c+4)+12c equation:


Simplifying
5(-3 + 4c) = 4(2c + 4) + 12c
(-3 * 5 + 4c * 5) = 4(2c + 4) + 12c
(-15 + 20c) = 4(2c + 4) + 12c

Reorder the terms:
-15 + 20c = 4(4 + 2c) + 12c
-15 + 20c = (4 * 4 + 2c * 4) + 12c
-15 + 20c = (16 + 8c) + 12c

Combine like terms: 8c + 12c = 20c
-15 + 20c = 16 + 20c

Add '-20c' to each side of the equation.
-15 + 20c + -20c = 16 + 20c + -20c

Combine like terms: 20c + -20c = 0
-15 + 0 = 16 + 20c + -20c
-15 = 16 + 20c + -20c

Combine like terms: 20c + -20c = 0
-15 = 16 + 0
-15 = 16

Solving
-15 = 16

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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