5(-3)+4=2(c-5)

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Solution for 5(-3)+4=2(c-5) equation: 



5(-3)+4=2(c-5)

We move all terms to the left:

5(-3)+4-(2(c-5))=0

We add all the numbers together, and all the variables

-(2(c-5))-11=0



We calculate terms in parentheses: -(2(c-5)), so:

2(c-5)

We multiply parentheses

2c-10

Back to the equation:

-(2c-10)



We get rid of parentheses

-2c+10-11=0

We add all the numbers together, and all the variables

-2c-1=0

We move all terms containing c to the left, all other terms to the right

-2c=1

c=1/-2

c=-1/2

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