5(-2-r)+5=-2(2r+2)

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Solution for 5(-2-r)+5=-2(2r+2) equation: 



5(-2-r)+5=-2(2r+2)

We move all terms to the left:

5(-2-r)+5-(-2(2r+2))=0

We add all the numbers together, and all the variables

5(-1r-2)-(-2(2r+2))+5=0

We multiply parentheses

-5r-(-2(2r+2))-10+5=0



We calculate terms in parentheses: -(-2(2r+2)), so:

-2(2r+2)

We multiply parentheses

-4r-4

Back to the equation:

-(-4r-4)



We add all the numbers together, and all the variables

-5r-(-4r-4)-5=0

We get rid of parentheses

-5r+4r+4-5=0

We add all the numbers together, and all the variables

-1r-1=0

We move all terms containing r to the left, all other terms to the right

-r=1

r=1/-1

r=-1

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