5(-2)-7c=40-2c

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Solution for 5(-2)-7c=40-2c equation: 



5(-2)-7c=40-2c

We move all terms to the left:

5(-2)-7c-(40-2c)=0

We add all the numbers together, and all the variables

-7c-(-2c+40)+5(-2)=0

We add all the numbers together, and all the variables

-7c-(-2c+40)-10=0

We get rid of parentheses

-7c+2c-40-10=0

We add all the numbers together, and all the variables

-5c-50=0

We move all terms containing c to the left, all other terms to the right

-5c=50

c=50/-5

c=-10

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