5(-10-6f)=-290

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Solution for 5(-10-6f)=-290 equation: 



5(-10-6f)=-290

We move all terms to the left:

5(-10-6f)-(-290)=0

We add all the numbers together, and all the variables

5(-6f-10)-(-290)=0

We add all the numbers together, and all the variables

5(-6f-10)+290=0

We multiply parentheses

-30f-50+290=0

We add all the numbers together, and all the variables

-30f+240=0

We move all terms containing f to the left, all other terms to the right

-30f=-240

f=-240/-30

f=+8

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