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5((1237-6y)/4)+5y=1435
We move all terms to the left:
5((1237-6y)/4)+5y-(1435)=0
We add all the numbers together, and all the variables
5((-6y+1237)/4)+5y-1435=0
We add all the numbers together, and all the variables
5y+5((-6y+1237)/4)-1435=0
We multiply all the terms by the denominator
5y*4)+5((-6y+1237)-1435*4)=0
We add all the numbers together, and all the variables
5y*4)+5((-6y+1237)=0
Wy multiply elements
20y^2=0
a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$y=\frac{-b}{2a}=\frac{0}{40}=0$
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