4z=12z-48

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Solution for 4z=12z-48 equation: 



4z=12z-48

We move all terms to the left:

4z-(12z-48)=0

We get rid of parentheses

4z-12z+48=0

We add all the numbers together, and all the variables

-8z+48=0

We move all terms containing z to the left, all other terms to the right

-8z=-48

z=-48/-8

z=+6

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