If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4z^2+3z+6=7
We move all terms to the left:
4z^2+3z+6-(7)=0
We add all the numbers together, and all the variables
4z^2+3z-1=0
a = 4; b = 3; c = -1;
Δ = b2-4ac
Δ = 32-4·4·(-1)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-5}{2*4}=\frac{-8}{8} =-1 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+5}{2*4}=\frac{2}{8} =1/4 $
| u/2-7=5 | | -4z+9=-6+z | | -4z+9=–6+z | | 3.5x-4=17 | | 2x+8=2(x+3)+2 | | 3(q-13)-4=5 | | 9(w+5)=9w | | 2-x=-x=2 | | 2(6z-6)=3(4+2z) | | -9(3m-10)=-10-7m | | 6/8=7+x/4 | | 6.4=w/3 | | 6x(5x-2)=-72 | | –20+10q=8q+18 | | 2(v+2)+1=9 | | -9h=4(-2h-5) | | -2(b-5)=-2 | | -(z-7)=2 | | 2(t-4)=4 | | -6f+10=-9f-2 | | -5j+10-7j=-2-8j | | 85-8x=2x+80 | | 5.5=25+4x | | -3v+8=-2-v+8 | | x^2+2x+1=4+1 | | -5q+6=-2+3q | | (x+1)2=5 | | x2+2x+1=4+1 | | 11x-45=8x-36 | | y+25=37 | | 3p+(2p+5)=30 | | 42-3=x |