4z/3-36=12-6z/3

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Solution for 4z/3-36=12-6z/3 equation: 



4z/3-36=12-6z/3

We move all terms to the left:

4z/3-36-(12-6z/3)=0

We add all the numbers together, and all the variables

4z/3-(-6z/3+12)-36=0

We get rid of parentheses

4z/3+6z/3-12-36=0

We multiply all the terms by the denominator


4z+6z-12*3-36*3=0

We add all the numbers together, and all the variables

10z-144=0

We move all terms containing z to the left, all other terms to the right

10z=144

z=144/10

z=14+2/5

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