4z-96=2z-40

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Solution for 4z-96=2z-40 equation: 



4z-96=2z-40

We move all terms to the left:

4z-96-(2z-40)=0

We get rid of parentheses

4z-2z+40-96=0

We add all the numbers together, and all the variables

2z-56=0

We move all terms containing z to the left, all other terms to the right

2z=56

z=56/2

z=28

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