4z-6=6(z+z)+8

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Solution for 4z-6=6(z+z)+8 equation: 



4z-6=6(z+z)+8

We move all terms to the left:

4z-6-(6(z+z)+8)=0

We add all the numbers together, and all the variables

4z-(6(+2z)+8)-6=0



We calculate terms in parentheses: -(6(+2z)+8), so:

6(+2z)+8

We multiply parentheses

12z+8

Back to the equation:

-(12z+8)



We get rid of parentheses

4z-12z-8-6=0

We add all the numbers together, and all the variables

-8z-14=0

We move all terms containing z to the left, all other terms to the right

-8z=14

z=14/-8

z=-1+3/4

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