4z-6=6(z+2)+2

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Solution for 4z-6=6(z+2)+2 equation: 



4z-6=6(z+2)+2

We move all terms to the left:

4z-6-(6(z+2)+2)=0



We calculate terms in parentheses: -(6(z+2)+2), so:

6(z+2)+2

We multiply parentheses

6z+12+2

We add all the numbers together, and all the variables

6z+14

Back to the equation:

-(6z+14)



We get rid of parentheses

4z-6z-14-6=0

We add all the numbers together, and all the variables

-2z-20=0

We move all terms containing z to the left, all other terms to the right

-2z=20

z=20/-2

z=-10

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