4z-48+4z=6z

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Solution for 4z-48+4z=6z equation:



4z-48+4z=6z
We move all terms to the left:
4z-48+4z-(6z)=0
We add all the numbers together, and all the variables
2z-48=0
We move all terms containing z to the left, all other terms to the right
2z=48
z=48/2
z=24

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