4z-2z+4z-3z+3z=12

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Solution for 4z-2z+4z-3z+3z=12 equation: 



4z-2z+4z-3z+3z=12

We move all terms to the left:

4z-2z+4z-3z+3z-(12)=0

We add all the numbers together, and all the variables

6z-12=0

We move all terms containing z to the left, all other terms to the right

6z=12

z=12/6

z=2

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