4z+80=2z+46

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Solution for 4z+80=2z+46 equation: 



4z+80=2z+46

We move all terms to the left:

4z+80-(2z+46)=0

We get rid of parentheses

4z-2z-46+80=0

We add all the numbers together, and all the variables

2z+34=0

We move all terms containing z to the left, all other terms to the right

2z=-34

z=-34/2

z=-17

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