4z+40=2(5z-1)

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Solution for 4z+40=2(5z-1) equation: 



4z+40=2(5z-1)

We move all terms to the left:

4z+40-(2(5z-1))=0



We calculate terms in parentheses: -(2(5z-1)), so:

2(5z-1)

We multiply parentheses

10z-2

Back to the equation:

-(10z-2)



We get rid of parentheses

4z-10z+2+40=0

We add all the numbers together, and all the variables

-6z+42=0

We move all terms containing z to the left, all other terms to the right

-6z=-42

z=-42/-6

z=+7

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