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4z+3=12+4z
We move all terms to the left:
4z+3-(12+4z)=0
We add all the numbers together, and all the variables
4z-(4z+12)+3=0
We get rid of parentheses
4z-4z-12+3=0
We add all the numbers together, and all the variables
-9!=0
There is no solution for this equation
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